1/2(x^2-y^2)-5/2(x^2-y^2)

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Solution for 1/2(x^2-y^2)-5/2(x^2-y^2) equation: 


x in (-oo:+oo)

(1/2)*(x^2-y^2)-((5/2)*(x^2-y^2)) = 0

(1/2)*(x^2-y^2)+(-5/2)*(x^2-y^2) = 0

1/2*(x^2-y^2)-5/2*(x^2-y^2) = 0

1/2*(x^2-y^2)-5/2*(x^2-y^2) = 0

2*y^2-2*x^2 = 0

2*y^2-2*x^2 = 0

-2*x^2 = -(2*y^2) // : -2

x^2 = y^2

x^2 = y^2 // ^ 1/2

abs(x) = y

x = y or x = -y

x in { y, -y }

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